Get dictionary from survey sheet
Usage
get_dictionary(data, survey, name_as_label = FALSE)
Arguments
- data
Some Kobo data.
- survey
Some survey sheet, with a split 'type' column, e.g. with split_survey(type). It must have columns 'list_name' and 'name'.
- name_as_label
Default to TRUE. Should the variable name be used as the label if label is missing?
